document.write( "Question 1113862: A chemist needs 150 milliliters of 62% solution but has only 12% and 87% solution available . find how many milliliters of each that should be mixed to get the desired solution? \n" ); document.write( "

Algebra.Com's Answer #728926 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "Here is an alternative to the standard algebraic method for solving this kind of mixture problem that I find much faster and easier than the formal algebraic method.

\n" ); document.write( "The ratio in which the two ingredients must be mixed is exactly determined by where the percentage of the mixture lies between the percentages of the two ingredients.

\n" ); document.write( "In this problem, the percentages of the ingredients are 12 and 87; the percentage of the mixture is 62. So we find how far the percentage of the mixture is from the percentage of each ingredient: 87-62=25; 62-12=50.

\n" ); document.write( "The ratio of those differences is the ratio in which the two ingredients need to be mixed: 25:50 = 1:2.

\n" ); document.write( "Since the 62% is closer to 87% than it is to 12%, the larger part of the mixture must be the 87% ingredient.

\n" ); document.write( "2:1 with a total of 150ml means 100ml of the 87% and 50ml of the 12%.

\n" ); document.write( "The explanation with words is lengthy; but here is all that is required to solve the problem:

\n" ); document.write( "87-62 = 25; 62-12 = 50; 25:50 = 1:2 = 50:100 --> 50ml of 12%, 100ml of 87% \n" ); document.write( "

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