document.write( "Question 1113853: Graph the rational function:
\n" ); document.write( "r(x)=(x-4)(x+1)/(x-1)(x+4)
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Algebra.Com's Answer #728924 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Graph the rational function:
\n" ); document.write( "\"r%28x%29=%28%28x-4%29%28x%2B1%29%29%2F%28%28x-1%29%28x%2B4%29%29\"

\n" ); document.write( "(1) zeros: The function value is 0 whenever the numerator is 0 -- when x=4 or x=-1.
\n" ); document.write( "(2) vertical asymptotes: The function is undefined and so has a vertical asymptote whenever the denominator is 0 -- when x=1 or x=-4.
\n" ); document.write( "(3) horizontal asymptote: As x gets very large (positive or negative) the constants become insignificant; the function value approaches x^2/x^2 = 1; the horizontal asymptote is y=1.

\n" ); document.write( "(4) intervals where the function value is positive or negative:

\n" ); document.write( "The x values -4, -1, 1, and 4 where the numerator or denominator is zero break the x axis into intervals; we need to determine whether the function value is positive or negative in each interval.

\n" ); document.write( "Most sources I have seen will tell you to use a test value in each interval. I find that process too repetitive; you can accomplish the same thing with less work if you simply imagine \"walking\" along the x axis and see what happens to the sign of the function value each time you cross from one of the intervals to the next.

\n" ); document.write( "For this problem, we can see that all 4 factors in the numerator and denominator are negative for large negative values of x; that means the function value is positive from negative infinity to x=-4.
\n" ); document.write( "Then when we pass x=-4, the sign of one factor changes; that changes the sign of the function value. So when we pass x=-4, the function value becomes negative.
\n" ); document.write( "Similarly, the function value changes from negative to positive when we pass x=-1; from positive to negative when we pass x=1, and finally from negative to positive when we pass x=4.

\n" ); document.write( "(5) Last we should find the values of x, if any, where the graph of the function crosses the horizontal asymptote. To do that, since the horizontal asymptote is y=1, we need to find all the solutions to
\n" ); document.write( "\"%28%28x-4%29%28x%2B1%29%29%2F%28%28x-1%29%28x%2B4%29%29=1\"
\n" ); document.write( "\"%28x-4%29%28x%2B1%29+=+%28x-1%29%28x%2B4%29\"
\n" ); document.write( "\"x%5E2-3x-4+=+x%5E2%2B3x-4\"
\n" ); document.write( "\"6x=0\"
\n" ); document.write( "\"x=0\"

\n" ); document.write( "The function value crosses the horizontal asymptote at x=0, and only there.

\n" ); document.write( "With all of the above, the basic behavior of the function is determined.

\n" ); document.write( "Here is a graph...:

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