document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113802>Question 1113802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> May I please to ask for your help to solve the following;<BR>\n" );
document.write( "How much of an alloy that is 40% copper should be mixed with 200 ounces of an alloy that is 70% copper in order to get an alloy that is 50% copper?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728895 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much of an alloy that is 40% copper should be mixed with 200 ounces of an alloy that is 70% copper in order to get an alloy that is 50% copper?<BR>\n" );
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document.write( "f = 40%<BR>\n" );
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document.write( "200*70 + f*40 = (200+f)*50 </SPAN>\n" );
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