document.write( "Question 1113797: Find an equation of a rational function f that satisfies the given conditions.
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document.write( "vertical asymptotes: x = −3, x = 0
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document.write( "horizontal asymptote: y = 0
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document.write( "x-intercept: 3; f(4) = 1 \n" );
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Algebra.Com's Answer #728892 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) vertical asymptotes: x = −3, x = 0 \n" ); document.write( "Vertical asymptotes (values of x where the function is undefined -- i.e., has no value) are caused by factors in the denominator that are equal to 0. If there are asymptotes at x=-3 and x=0, then there are factors of (x+3) and x in the denominator. \n" ); document.write( " \n" ); document.write( "(2) horizontal asymptote: y = 0 \n" ); document.write( "The horizontal asymptote is 0 if the degree of the numerator is less than the degree of the numerator. We'll come back to this one.... \n" ); document.write( "(3) x-intercept: 3 \n" ); document.write( "An x-intercept (where the function value is 0) is caused by a factor in the numerator that is equal to 0. If there is an x-intercept at x=3, there must be a factor of (x-3) in the numerator. \n" ); document.write( " \n" ); document.write( "Note that the degree of the numerator at this point is less than the degree of the denominator; so the condition for having a horizontal asymptote of y=0 is satisfied. So we have all the factors of our rational function that contain variables; we now need to find the constant factor. \n" ); document.write( "(4) f(4) = 1 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Our rational function is \n" ); document.write( " \n" ); document.write( "A graph... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |