document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113790>Question 1113790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let X and Y be Markov chains on the set;Z of integers. Is the sequence Zn = Xn + Yn necessarily a Markov chain? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728886 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No<BR>\n" );
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document.write( "if you know Z(n-1) = X(n-1) + Y(n-1), there is no way you can know X(n-1) and Y(n-1) - this means you can not find the distribution of X(n) + Y(n) from the knowledge of X(n-1) + Y(n-1)<BR>\n" );
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