document.write( "Question 1113773: solve for x if [3 1 0
\n" ); document.write( " 2 x 1
\n" ); document.write( " 4 5 -2] = 0
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Algebra.Com's Answer #728861 by Alan3354(69443)\"\" \"About 
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solve for x if [3 1 0
\n" ); document.write( " 2 x 1
\n" ); document.write( " 4 5 -2] = 0
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document.write( "|3   1   0|\r\n" );
document.write( "|2   x   1| = 0\r\n" );
document.write( "|4   5  -2|\r\n" );
document.write( "===============\r\n" );
document.write( "|2   x   1|\r\n" );
document.write( "|3   1   0| = 0\r\n" );
document.write( "|4   5  -2|\r\n" );
document.write( "=================\r\n" );
document.write( "|x   2   1|\r\n" );
document.write( "|1   3   0| = 0\r\n" );
document.write( "|5   4  -2|\r\n" );
document.write( "---------\r\n" );
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\n" ); document.write( "x*(-6-0) - 2*(-1-0) + 1*(4-15) = 0
\n" ); document.write( "-6x + 2 - 11 = 0
\n" ); document.write( "-6x = 9
\n" ); document.write( "x = -3/2
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\n" ); document.write( "the transposing is not necessary, but it gives just one term with x.
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