document.write( "Question 1113759: The sum of the series 1/√3+1+3/√3+........... To 18 terms is ??
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Algebra.Com's Answer #728853 by KMST(5328)\"\" \"About 
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It is a geometric series, with first term \"b=1%2Fsqrt%283%29\" and common ratio \"r=sqrt%283%29\" .
\n" ); document.write( "The sum of the first \"n\" terms of a geometric series with first term \"b\" and common ratio \"r\" is
\n" ); document.write( "\"b%28%28r%5En-1%29%2F%28r-1%29%29\" .
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\n" ); document.write( "In this case, the sum of the first \"n=18\" terms would be
\n" ); document.write( "\"%281%2Fsqrt%283%29%29%28%28sqrt%283%29%5E18-1%29%2F%28sqrt%283%29-1%29%29\"\"%22=%22\"\"%281%2Fsqrt%283%29%29%28%28%283%5E%221+%2F+2%22%29%5E18-1%29%2F%28sqrt%283%29-1%29%29\"\"%22=%22\"\"%22=%22\"\"%22=%22\"\"19682%283%2Bsqrt%283%29%29%2F%283%283-1%29%29\"\"%22=%22\"\"19682%283%2Bsqrt%283%29%29%2F6\"\"%22=%22\"\"highlight%289841%283%2Bsqrt%283%29%29%2F3%29\"\"%22=%22\"\"approximately15522.7\"
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\n" ); document.write( "ANOTHER WAY:
\n" ); document.write( "The 9 even numbered terms are
\n" ); document.write( "\"matrix%281%2C7%2C%0D%0A1%2C%22%2C%22%2C3%2C%22%2C%22%2C9%2C%22%2C...%2C%22%2C3%5E8=6561%29\" and add up to \"1%283%5E9-1%29%2F%283-1%29=%2819683-1%29%2F2=9841\" .
\n" ); document.write( "The 9 odd numbered terms must add up to \"9841%2Fsqrt%283%29\" .
\n" ); document.write( "Adding up both of those sums, we get
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