document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113713>Question 1113713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of x and y:<BR>\n" );
document.write( "Have a parrallegram bisected into 4 quadrants: 1 on top is 2y-2, one on right is 2y, one on bottom is x+y, one on left is 3x. If I'd set up equation I'd have an x and y on the same problem..how do I do??<BR>\n" );
document.write( "2y-2=x+y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728835 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you break the parallelogram into 4 quadrants by drawing two diagonals to connect opposite corners of the parallelogram.\r<BR>\n" );
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document.write( "this creates two sets of congruent triangles.\r<BR>\n" );
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document.write( "the top triangle is congruent to the bottom triangle.<BR>\n" );
document.write( "the left triangle is congruent to the right triangle.\r<BR>\n" );
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document.write( "they are congruent by SSS.\r<BR>\n" );
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document.write( "that's why you get 2y-2 = x+y and 3x = 2y\r<BR>\n" );
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document.write( "you have 2 equations that need to be solved simultaneously because the same value of x and the same value of y applies to both equations.\r<BR>\n" );
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document.write( "start with:\r<BR>\n" );
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document.write( "2y-2 = x+y<BR>\n" );
document.write( "3x = 2y\r<BR>\n" );
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document.write( "use either equation to solve for x or y.\r<BR>\n" );
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document.write( "i chose the second equation to solve for x.\r<BR>\n" );
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document.write( "i got x = (2/3) * y\r<BR>\n" );
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document.write( "i then replaced x with (2/3) * y in the first equation to get:\r<BR>\n" );
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document.write( "2y-2 = (2/3) * y + y\r<BR>\n" );
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document.write( "this is one equation in one variable that can give you a unique solution.\r<BR>\n" );
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document.write( "combine like terms to get 2y-2 = 5/3 * y\r<BR>\n" );
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document.write( "subtract 5/3 * y from both sides of the equation and add 2 to both sides of the equation to get:\r<BR>\n" );
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document.write( "2y - 5/3 * y = 2\r<BR>\n" );
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document.write( "multiply both sides of the equation by 3 to get:\r<BR>\n" );
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document.write( "6y - 5y = 6\r<BR>\n" );
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document.write( "solve for y to get y = 6\r<BR>\n" );
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document.write( "in the second equation, replace y with 6 to get:\r<BR>\n" );
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document.write( "3x = 2y becomes 3x= 12.\r<BR>\n" );
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document.write( "solve for x to get x = 4\r<BR>\n" );
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document.write( "that's your solution.\r<BR>\n" );
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document.write( "x = 4 and y = 6\r<BR>\n" );
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document.write( "3x = 2y becomes 3*4 = 2*6 which becomes 6 = 6 which is true.\r<BR>\n" );
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document.write( "2y-2 = x+y becomes 2*6-2 = 4+6 becomes 12-2 = 10 which becomes 10 = 10 which is true.\r<BR>\n" );
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document.write( "solution is confirmed to be good.\r<BR>\n" );
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document.write( "presumably the area of each triangleis equa </SPAN>\n" );
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