document.write( "Question 1113714: a 20% dye solution is to be mixed with 59% solution to get 260 l of a 50% solution how many liters of a 20% and 59% solutions will be needed \n" ); document.write( "
Algebra.Com's Answer #728806 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
20%? 59%?
\n" ); document.write( "What kind of dye? What kind of solvent?\r
\n" ); document.write( "\n" ); document.write( "Not \"solution\", but maybe DISPERSION!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use \"L\" for liters; not \"l\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x of the 20%
\n" ); document.write( "260-x of the 59%\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"20x%2B59%28260-x%29=50%2A260\"
\n" ); document.write( "Solve this for x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If the algebra done carefully, find \"highlight%28x=60%29\" for the 20% dispersion, and therefore \"highlight%28200%29\" for the 59% dispersion dye.
\n" ); document.write( "
\n" );