document.write( "Question 965979: prove that the product of any three consecutive numbers is even.
\n" ); document.write( "So far I have tried , (n)(n+1)(n+2)=n^3+3n^2+2n
\n" ); document.write( "but there is no multiple of an even number. I'm not sure what kind of proof method it is but this would be a proof with the same method. i.e prove that the sum of three consecutive odd numbers is divisible by 3 , 2n+1+2n+3+2n+5= 6n+9 3(2n+3) is a multiple of three therefore it is divisible by three.\r
\n" ); document.write( "\n" ); document.write( "Any help would be appreciated, hope it is not too confusing
\n" ); document.write( "Thanks
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #728794 by amalm06(224)\"\" \"About 
You can put this solution on YOUR website!
Consider \"%28n%29%28n%2B1%29%28n%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Then , where the last expression is even \n" ); document.write( "
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