document.write( "Question 1113675: Solve for x and y, 3x + iy = (1 + i)(x^2 + y^2). Ans: x = 3/10 and y = 9/10 \n" ); document.write( "
Algebra.Com's Answer #728756 by math_helper(2461)\"\" \"About 
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\"+3x+%2B+yi+=+%281%2Bi%29%28x%5E2%2By%5E2%29+\"\r
\n" ); document.write( "\n" ); document.write( "Let \"+k=x%5E2%2By%5E2+\" for now:\r
\n" ); document.write( "\n" ); document.write( "\"++3x%2Byi+=+%281%2Bi%29k+\"
\n" ); document.write( "\"++3x%2Byi+=+k%2Bki+\"
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\n" ); document.write( "\n" ); document.write( "Using Re{LHS} = Re{RHS}, Im{LHS}=Im{RHS} :
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document.write( "3x = k  —>  x = k/3  (1)\r\n" );
document.write( "y = k                (2) 
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\n" ); document.write( "\n" ); document.write( "But \"+x%5E2%2By%5E2+=+k+\" so, using (1) and (2):
\n" ); document.write( "\"+k%5E2%2F9+%2B+k%5E2++=+k+\"
\n" ); document.write( "\"++10k%5E2+-+9k+=+0+\"
\n" ); document.write( "k=0 and/or k=9/10\r
\n" ); document.write( "\n" ); document.write( "k=0 is a trivial solution (x=y=k=0)
\n" ); document.write( "k=9/10 —> \"+highlight%28+x+=+3%2F10%29+\" , \"+highlight%28++y+=+9%2F10%29+\"
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