document.write( "Question 1113638: Wilma is 13 years older than Bev. In nine years, Wilma will be twice as old as Bev. How old is Bev? \n" ); document.write( "
Algebra.Com's Answer #728715 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let w be Wilma's age and b be Bev's age \n" ); document.write( ": \n" ); document.write( "1) w = b +13 \n" ); document.write( ": \n" ); document.write( "2) w +9 = 2(b+9) \n" ); document.write( ": \n" ); document.write( "use equation 1 and substitute for w in equation 2 \n" ); document.write( ": \n" ); document.write( "b +13 +9 = 2b +18 \n" ); document.write( ": \n" ); document.write( "b = 4 \n" ); document.write( "w = 4 +13 = 17 \n" ); document.write( ": \n" ); document.write( "***************************** \n" ); document.write( "Wilma is 17 and Bev is 4 \n" ); document.write( ": \n" ); document.write( "check answer in equation 2 \n" ); document.write( ": \n" ); document.write( "17 +9 = 2(4+9) \n" ); document.write( ": \n" ); document.write( "26 = 26 \n" ); document.write( "******************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |