document.write( "Question 1113584: If A is an angle such that tanA+secA=2, evaluate cosA. \n" ); document.write( "
Algebra.Com's Answer #728714 by MathTherapy(10552)\"\" \"About 
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If A is an angle such that tanA+secA=2, evaluate cosA.
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\"matrix%281%2C3%2C+tan+%28A%29+%2B+sec+%28A%29%2C+%22=%22%2C+2%29\"
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document.write( "\"matrix%281%2C3%2C+tan+%28A%29%2C+%22=%22%2C+2+-+sec+%28A%29%29\"
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document.write( "\"matrix%281%2C3%2C+tan%5E2+%28A%29%2C+%22=%22%2C+4+-+4+sec+%28A%29+%2B+sec%5E2+%28A%29%29\" -------- Squaring each side of equation
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document.write( "\"matrix%281%2C3%2C+sec%5E2+%28A%29+-+1%2C+%22=%22%2C+4+-+4+sec+%28A%29+%2B+sec%5E2+%28A%29%29\" ----- Substituting \"matrix%281%2C3%2C+sec%5E2+%28A%29+-+1%2C+for%2C+tan%5E2+%28A%29%29\"
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document.write( "\"matrix%281%2C3%2C+sec%5E2+%28A%29+-+1+-+sec%5E2+%28A%29+%2B+4+sec+%28A%29%2C+%22=%22%2C+4%29\"
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document.write( "4 sec A = 5
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document.write( "\"highlight_green%28matrix%281%2C3%2C+cos+%28A%29%2C+%22=%22%2C+4%2F5%29%29\" \n" );
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