document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113600>Question 1113600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A piece of ice is 3' * 10.5\" * 10.5\".  Specific gravity of ice is .92.<BR>\n" );
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document.write( "SG --> units of grams/cc\r<BR>\n" );
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document.write( "Determine:\r<BR>\n" );
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document.write( "A) Amount of water in the ice.\r<BR>\n" );
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document.write( "B) Weight of ice.\r<BR>\n" );
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document.write( "3 * .875 * .875 = 2.296875 cu. ft. (Volume of ice).\r<BR>\n" );
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document.write( "Unsure how to solve.  Non-homework. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728698 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A piece of ice is 3' * 10.5\" * 10.5\".  Specific gravity of ice is .92.\r<BR>\n" );
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document.write( "Determine:\r<BR>\n" );
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document.write( "A) Amount of water in the ice.<BR>\n" );
document.write( "3 * .875 * .875 = 2.296875 cu. ft. (Volume of ice).\r<BR>\n" );
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document.write( "B) Weight of ice.<BR>\n" );
document.write( "Weight (or mass) = Vol*density<BR>\n" );
document.write( "Density of water = 62.372 pounds/cu ft<BR>\n" );
document.write( "W = 62.372*2.296875*0.92<BR>\n" );
document.write( "W =~ 131.8 pounds<BR>\n" );
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