document.write( "Question 100060: given the following two complex numbers, a=3+7i and b=-2-2i,calculate the following
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document.write( "a+b
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document.write( "a-b
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document.write( "a*b
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document.write( "a/b \n" );
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Algebra.Com's Answer #72863 by edjones(8007)![]() ![]() You can put this solution on YOUR website! a=3+7i b=-2-2i \n" ); document.write( ". \n" ); document.write( "a+b \n" ); document.write( "3+7i+(-2-2i) \n" ); document.write( "3+7i-2-2i \n" ); document.write( "group like terms: (3-2)+(7i-2i) \n" ); document.write( "1+5i Ans. \n" ); document.write( ". \n" ); document.write( "a-b \n" ); document.write( "3+7i-(-2-2i) \n" ); document.write( "3+7i+2+2i \n" ); document.write( "(3+2)+(7i+2i) \n" ); document.write( "5+9i Ans \n" ); document.write( ". \n" ); document.write( "a*b \n" ); document.write( "(3+7i)*(-2-2i) \n" ); document.write( "-6-20i-14i^2 \n" ); document.write( "-6-20i+14 \n" ); document.write( "8-20i Ans \n" ); document.write( ". \n" ); document.write( "a/b \n" ); document.write( "Here it gets a little tricky. \n" ); document.write( "(3+7i)/(-2-2i) \n" ); document.write( "multiply the top and bottom by complex congugate of the denominator: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Ed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |