document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113542>Question 1113542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi i think im close but still cant get this one. \r<BR>\n" );
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document.write( "sum of three numbers =129<BR>\n" );
document.write( "second number is 9 less the first<BR>\n" );
document.write( "third number is 3 times the second\r<BR>\n" );
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document.write( "1st #=<BR>\n" );
document.write( "2nd #=<BR>\n" );
document.write( "3rd #= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728600 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x, y, and z are the numbers<BR>\n" );
document.write( "x+y+z=129<BR>\n" );
document.write( "y=x-9<BR>\n" );
document.write( "z=3(x-9)<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( "x+x-9+3x-27=129<BR>\n" );
document.write( "5x-36=129<BR>\n" );
document.write( "5x=165<BR>\n" );
document.write( "x=33<BR>\n" );
document.write( "the numbers are 33, 24, and 72, and they add to 129. </SPAN>\n" );
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