document.write( "Question 1113459: A wire 10 cm long is cut into two pieces, one of length x and the other of length x and the other of length 10-x. Each piece is bent into a shape of square. Which of the following is the model for the total area enclosed by the two squares of function of x?
\n" ); document.write( "a. \"A%28x%29=+%28x%5E2-5x%2B50%29%2F8\"
\n" ); document.write( "b. \"A%28x%29=+%282x%5E2%2B100%29%2F16\"
\n" ); document.write( "c. \"A%28x%29=+%28x%5E2-10x%2B50%29%2F8\"
\n" ); document.write( "d. \"A%28x%29=+%28x%5E2%2B100%29%2F16\"
\n" ); document.write( "After finding the total area, what is the value of x that minimizes the total area of the two squares? CHOICES(3 cm, 4cm, 5cm, and 6cm)
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Algebra.Com's Answer #728492 by math_helper(2461)\"\" \"About 
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The first (x) length makes a square that has area \"+A%5B1%5D+=++%28x%2F4%29%5E2+\"
\n" ); document.write( "The 2nd length is 10-x, so it makes a square that has area \"+A%5B2%5D+=+%28%2810-x%29%2F4%29%5E2+\"\r
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\n" ); document.write( "I will use Calculus to find the minimum:\r
\n" ); document.write( "\n" ); document.write( "First we take the 1st derivative of A with respect to x (giving us the rate of change of A with respect to x):
\n" ); document.write( " \"+%28dA%2Fdx%29+=+%282x-10%29%2F8+\" —> This is zero when x = 5cm. So 5cm is a critical point.\r
\n" ); document.write( "\n" ); document.write( "The 2nd derivative of A with respect to x tells us if the function is curved up or curved down (at x=5):
\n" ); document.write( " \"+%28d%5E2A%2Fdx%5E2%29+=+2+\" so the curve is curved up (concave up) everywhere which means the critical point is at a minimum.\r
\n" ); document.write( "\n" ); document.write( "\"+highlight%28+5cm+%29+\" minimizes the area.
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\n" ); document.write( "\n" ); document.write( "Since this problem was multiple choice, the endpoints x=0 and x=10 need not be considered. In solving min/max problems in general, one must consider the function value at the endpoints in addition to at all critical points found.
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\n" ); document.write( "To figure out the minimum without Calculus, one way to see the minimum is to plot the graph of the function (x along the x-axis, A(x) along the y axis). Since this was multiple choice, you'd plot (compute A(x)) for the 4 values given, and compare their heights. When plotting a function in general you would take use x values and plot more A(x) values.
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