document.write( "Question 1113391: Hey would you please help me with this? I'm pretty sure it's either A or B\r
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\n" ); document.write( "\n" ); document.write( "Which system of equations can be used to solve the following problem? \r
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\n" ); document.write( "\n" ); document.write( "Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $150, and 40 tickets were sold, how many of each type of ticket were sold? Let c be the number of child tickets and a be the number of adult tickets.
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\n" ); document.write( "A.
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\n" ); document.write( "5c+3a=150
\n" ); document.write( "c+a=40
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\n" ); document.write( "B.
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\n" ); document.write( "\n" ); document.write( "3c+5a=150
\n" ); document.write( "a+c=40
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\n" ); document.write( "C.
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\n" ); document.write( "\n" ); document.write( "3a+5c=40
\n" ); document.write( "a+c=150
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\n" ); document.write( "D.
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\n" ); document.write( "\n" ); document.write( "3c+5a=40
\n" ); document.write( "a+c=150
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Algebra.Com's Answer #728432 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
B
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\n" ); document.write( "1) a + c = 40
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\n" ); document.write( "2) 3c +5a = 150
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\n" ); document.write( "solve equation 1 for c
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\n" ); document.write( "c = 40 -a
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\n" ); document.write( "substitute for c in equation 2
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\n" ); document.write( "3(40 -a) +5a = 150
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\n" ); document.write( "120 -3a +5a = 150
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\n" ); document.write( "2a = 30
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\n" ); document.write( "a = 15
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\n" ); document.write( "c = 40 -15 = 25
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\n" ); document.write( "25 children(c) and 15 adults(a)
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\n" ); document.write( "check the answer
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\n" ); document.write( "3(25) +5(15) = 150
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\n" ); document.write( "75 +75 = 150
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\n" ); document.write( "150 = 150
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