document.write( "Question 1113405: a survey report states that 37% of adults visit their doctor regularly. suppose that 10 adults are selected at random. what is the probability that exactly 8 adults visit their doctor regularly in such group?
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Algebra.Com's Answer #728430 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! use the binomial probability formula \n" ); document.write( ": \n" ); document.write( "Probability (P) ( k successes in n trials ) = nCk * p^k * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!) \n" ); document.write( ": \n" ); document.write( "for this problem n=10, k=8, p=0.37 \n" ); document.write( ": \n" ); document.write( "P (8 adults visit their doctor regularly out of 10 selected) = 10C8 * (0.37)^8 * (1-0.37)^(10-8) = 0.0063 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |