document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113404>Question 1113404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the stopping distance, s, of a car varies directly as the square of its speed, v. If a car traveling 60 mph requires 220ft to stop find the stopping distance for a car traveling 30 mph </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728421 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the stopping distance, s, of a car varies directly as the square of its speed, v. If a car traveling 60 mph requires 220ft to stop find the stopping distance for a car traveling 30 mph<BR>\n" );
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document.write( "d = k*v^2 --- k is a constant<BR>\n" );
document.write( "220 = k*60^2<BR>\n" );
document.write( "k = 220/3600<BR>\n" );
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document.write( "at 30 mi/hr:<BR>\n" );
document.write( "d = (220/3600)*30^2<BR>\n" );
document.write( "d = 55 feet\r<BR>\n" );
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document.write( " </SPAN>\n" );
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