document.write( "Question 99868: a collection of nickels dimes and quarters in a money bag worth 33.50 number of quarters is five times the number of nickels and the number of dimes is five less than four times the number of nickels find the number of each type of coin. \n" ); document.write( "
Algebra.Com's Answer #72839 by ptaylor(2198) You can put this solution on YOUR website! Let x=the number of nickels; Value of the nickels=0.05x \n" ); document.write( "Then 5x=number of quarters; Value of the quarters=0.25(5x) or 1.25x \n" ); document.write( "And 4x-5=number of dimes; Value of the dimes=0.10(4x-5) \r \n" ); document.write( "\n" ); document.write( "Now we are told that the value of these coins adds up to $33.50 so our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "0.05x+1.25x+0.10(4x-5)=$33.50 get rid of parens\r \n" ); document.write( "\n" ); document.write( "0.05x+1.25x+0.4x-0.5=33.50 add 0.5 to both sides\r \n" ); document.write( "\n" ); document.write( "0.05x+1.25x+0.4x-0.5+0.5=33.50+0.5 collect like terms\r \n" ); document.write( "\n" ); document.write( "1.7x=34 divide both sides by 1.7\r \n" ); document.write( "\n" ); document.write( "x=20----------------number of nickels \n" ); document.write( "5x=5*20=100-----------------number of quarters\r \n" ); document.write( "\n" ); document.write( "4x-5=4*20-5=75-----------number of dimes\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "0.05*20+0.25*100+0.10*75=33.50 \n" ); document.write( "1+25+7.50=33.50 \n" ); document.write( "33.50=33.50\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |