document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113307>Question 1113307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bag contain 8 red 6 blue balls.two drawing of each 2 ballasts made find the probability that the first drawing two red balls and second drawing 2 blue balls, if the balls drawn first are replaced before the second draw </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728316 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are 14 balls in the bag <BR>\n" );
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document.write( "Probability of drawing two red balls = (8/14) * (7/13) = 4/13<BR>\n" );
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document.write( "Probability of drawing two blue balls = (6/14) * (5/13) = 15/91<BR>\n" );
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document.write( "Probability of drawing 2 red balls and 2 blue balls = (4/13) * (15/91) = 60/1183 <BR>\n" );
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document.write( "Note I assume a single ball drawn is not replaced until after the second ball is drawn<BR>\n" );
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