document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99971>Question 99971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the complement of an angle less the supplement of an angle is 10 degrees. Find the supplement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72830 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=the angle<BR>\n" );
document.write( "supplement=180-x<BR>\n" );
document.write( "complement=90-x<BR>\n" );
document.write( "3(90-x)-(180-x)=10<BR>\n" );
document.write( "270-3x-180+x=10<BR>\n" );
document.write( "90-2x=10<BR>\n" );
document.write( "subtract 90 from each side: -2x=-80<BR>\n" );
document.write( "divide -2 into each side: x=40<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "3*50-140=10<BR>\n" );
document.write( "150-140=10<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );