document.write( "Question 1113289:
\n" ); document.write( "Two pipes can be used to fill a pool. Working​ together, the two pipes can fill the pool in 8 hours. The larger pipe can fill the pool in 4 hours less time than the smaller pipe can alone. Find the time to the nearest tenth of an hour it takes for the smaller pipe working alone to fill the pool.
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Algebra.Com's Answer #728291 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Filling the pool is 1 job
\n" ); document.write( "Pipe A + pipe B takes 8 hours
\n" ); document.write( "So they will do 1 / 8 of the job in 1 hour
\n" ); document.write( "Pipe A alone takes x hours
\n" ); document.write( "It does 1 / x of the job in 1 hour
\n" ); document.write( "Pipe B does the job in x -4 hours
\n" ); document.write( "Pipe B does 1/(x -4 ) of the job in 1 hour
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\n" ); document.write( "1/x + 1/(x -4 )= 1 / 8
\n" ); document.write( "Simplify
\n" ); document.write( "(x -4 +x/((x)(x -4 )= 1 / 8
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\n" ); document.write( "8 (2x-4)= x^2 -4 x
\n" ); document.write( "16 x -32 = x^2 -4 x
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\n" ); document.write( "x^2- -20 x+ 32 = 0\r
\n" ); document.write( "\n" ); document.write( "solve the quadratic equation by formula method
\n" ); document.write( "x=18.2
\n" ); document.write( "x-4 =14.2\r
\n" ); document.write( "\n" ); document.write( "One pipe 18.2 hours to fillalone
\n" ); document.write( "Pipe B 14.2 hours to fill alone \r
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