document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113230>Question 1113230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alika is training for a paddleboard race between Molokai and Oahu.  He knows he can average 5 mph with no current.  During a recent training run in the ocean, he noticed it took the same amount of time to travel 10 miles with the current as it did to travel 6 miles against the current.  What was the rate of the current that day?\r<BR>\n" );
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document.write( "thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728270 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> v*t=distance<BR>\n" );
document.write( "(5-c)*t=6<BR>\n" );
document.write( "(5+c)*t=10, where c is the current<BR>\n" );
document.write( "t=6/(5-c)<BR>\n" );
document.write( "t also = (10)/(5+c)<BR>\n" );
document.write( "Those two are equal since the times are stated to be equal.<BR>\n" );
document.write( "cross multiply<BR>\n" );
document.write( "6(5+c)=10(5-c)<BR>\n" );
document.write( "30+6c=50-10c<BR>\n" );
document.write( "16c=20<BR>\n" );
document.write( "c=1.25 mph ANSWER<BR>\n" );
document.write( "check<BR>\n" );
document.write( "3.75 mph against and takes 6/3.75 or 1.6 hours to go 6 miles.<BR>\n" );
document.write( "6.25 mph with and takes 1.6 hours to go 10 miles<BR>\n" );
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