document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100008>Question 100008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of a liquid with a 30% alchohol content and how much of a liquid with a 100% alcohol content should be added to end up with 42 milliiters of with a 50% alcohol content?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72826 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [ 100%(x) + 30%(42 - x) ]/[42] = 50%<BR>\n" );
document.write( "[ x + 0.3(42 - x) ]/42 = 0.5<BR>\n" );
document.write( "[ x + 12.6 - 0.3x ]/42 = 0.5<BR>\n" );
document.write( "[ 0.7x + 12.6 ]/42 = 0.5<BR>\n" );
document.write( "0.7x + 12.6 = 21<BR>\n" );
document.write( "0.7x = 8.4<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "42 - x = 30<BR>\n" );
document.write( "12mL of 100% and 30mL of 30% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );