document.write( "Question 1113199: The drama club is earning money for sets through its ticket sales for the school play. Tickets purchased in advance cost $4 and tickets sold at the door cost $5.50. Altogether the drama club earned 4$40 in ticket sales. If there were 15 more tickets sold in advance than at the door, how many of each price were sold? \n" ); document.write( "

Algebra.Com's Answer #728211 by mananth(16946) $\"\"$ $\"About$

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\n" ); document.write( "
\n" ); document.write( "$4 x Advance tickets
\n" ); document.write( "$5.50 y sold at door
\n" ); document.write( "Equation for total investors
\n" ); document.write( "
\n" ); document.write( " x - y = 15 .............1
\n" ); document.write( "
\n" ); document.write( "Equation for amount raised
\n" ); document.write( "$4 x + 5.50 y = $440 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 5.50
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "5.50 x -5.50 y = 82.50
\n" ); document.write( "4.00 5.50 y = 440.00
\n" ); document.write( "Add the two equations
\n" ); document.write( "9.50 x = 522.50
\n" ); document.write( "/ 9.50
\n" ); document.write( "x = 55.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( " x + - y = 15
\n" ); document.write( "55 + - y = 15
\n" ); document.write( " - y = -40
\n" ); document.write( " y= 40
\n" ); document.write( "
\n" ); document.write( " 55 Advance tickets
\n" ); document.write( " 40 at the door tickets
\n" ); document.write( " \n" ); document.write( "

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