document.write( "Question 1113128: y varies jointly as a and b, and inversely as the square root of c. If y=135 when a=3, b=9, and c=4; then find y when a=12, b=7, and c=9.\r
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Algebra.Com's Answer #728164 by josmiceli(19441)\"\" \"About 
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Let \"+k%5Ba%5D+\", \"+k%5Bb%5D+\", and \"+k%5Bc%5D+\"
\n" ); document.write( "= constants of proportionality
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\n" ); document.write( "(1) \"+y+=+k%5Ba%5D%2Aa+\"
\n" ); document.write( "(2) \"+y+=+k%5Bb%5D%2Ab+\"
\n" ); document.write( "(3) \"+y+=+k%5Bc%5D%2A%28+1%2Fsqrt%28c%29+%29+\"
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\n" ); document.write( "(1) \"+135+=+k%5Ba%5D%2A3+\"
\n" ); document.write( "(1) \"+k%5Ba%5D+=+45+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+135+=+k%5Bb%5D%2A9+\"
\n" ); document.write( "(2) \"+k%5Bb%5D+=+15+\"
\n" ); document.write( "and
\n" ); document.write( "(3) \"+135+=+k%5Bc%5D%2A%28+1%2Fsqrt%284%29+%29+\"
\n" ); document.write( "(3) \"+k%5Bc%5D+=+135%2Asqrt%284%29+\"
\n" ); document.write( "(3) \"+k%5Bc%5D+=+135%2A2+\"
\n" ); document.write( "(3) \"+k%5Bc%5D+=+270+\"
\n" ); document.write( "=======================
\n" ); document.write( "\"+a+=+12+\"
\n" ); document.write( "(1) \"+y+=+k%5Ba%5D%2A12+\"
\n" ); document.write( "(1) \"+y+=+45%2A12+\"
\n" ); document.write( "(1) \"+y+=+540+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+b+=+7+\"
\n" ); document.write( "(2) \"+y+=+k%5Bb%5D%2A7+\"
\n" ); document.write( "(2) \"+y+=+15%2A7+\"
\n" ); document.write( "(2) \"+y+=+105+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+c+=+7+\"
\n" ); document.write( "(3) \"+y+=+k%5Bc%5D%2A%28+1%2Fsqrt%28c%29+%29+\"
\n" ); document.write( "(3) \"+y+=+270%2A%28+1%2Fsqrt%289%29+%29+\"
\n" ); document.write( "(3) \"+y+=+270%2F3+\"
\n" ); document.write( "(3) \"+y+=+90+\"
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