document.write( "Question 1113069: factorise:
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Algebra.Com's Answer #728124 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "1.  Introduce new variable  u = 2x-3.\r\n" );
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document.write( "    Then your polynomial takes the form  6u^2 - 5u - 4.\r\n" );
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document.write( "2.  Then you can factorize the last polynomial\r\n" );
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document.write( "    6u^2 - 5u - 4 = (3u-4)*(2u+1).                      (1)\r\n" );
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document.write( "3.  Now substitute back (2x-3) instead of \"u\" into (1).  You will get\r\n" );
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document.write( "    6(2x-3)^2-5(2x-3)-4 = (3*(2x-3)-4)*(2*(2x-3)+1)     (2)\r\n" );
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document.write( "4.  Your next and final step is to simplify (2):\r\n" );
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document.write( "     6(2x-3)^2-5(2x-3)-4 = (3*(2x-3)-4)*(2*(2x-3)+1) = (6x-13)*(4x-5).\r\n" );
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document.write( "Answer.  6(2x-3)^2-5(2x-3)-4 = (6x-13)*(4x-5).\r\n" );
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