document.write( "Question 1113037: From a committee consisting of 5 men and 6 women, a sub-committee is formed consisting of 4 men and 3 women. How many different subcommittees are possible? \n" ); document.write( "
Algebra.Com's Answer #728116 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The number of ways of choosing 4 of the 5 men is C(5,4) \"5 choose 4\" = 5. \n" ); document.write( "The number of ways of choosing 3 of the 6 women is C(6,3) \"6 choose 3\" = (6*5*4)/(3*2*1) = 20. \n" ); document.write( "The number of ways of choosing 4 of th5 men AND 3 of the 6 women is C(5,4) times C(6,3) = 5*20 = 100. \n" ); document.write( " |