document.write( "Question 1113030: Solve the logarithm equation. Type exact answer. 2logx-log(4x-40)-1=0 \n" ); document.write( "
Algebra.Com's Answer #728078 by Alan3354(69443)\"\" \"About 
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2logx-log(4x-40)-1=0
\n" ); document.write( "If it's base 10:
\n" ); document.write( "log(x^2)-log(4x-40) = 1 = log(10)
\n" ); document.write( "log(x^2)-log(4x-40) = 1 = log(10)
\n" ); document.write( "log(x^2) = log(4x-40) + log(10)
\n" ); document.write( "log(x^2) = log(10*(4x-40)) = log(40x - 400)
\n" ); document.write( "x^2 = 40x - 400
\n" ); document.write( "x^2 - 40x + 400 = 0
\n" ); document.write( "(x-20)^2 = 0
\n" ); document.write( "x = 20
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