document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1112965>Question 1112965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help? Thank you. <BR>\n" );
document.write( "A ship leaves port and travels along a bearing of S 25 degree W for 18km, then turns on a bearing of S 65 degree E for 25km. <BR>\n" );
document.write( "a. How far from port is this ship at the end of these two legs of the trip?<BR>\n" );
document.write( "b. On what bearing must the ship travel to return to port? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #728051 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=728051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If this is drawn out, it is a right triangle with legs of 18 and 25 with the hypotenuse the distance from port<BR>\n" );
document.write( "hypot^2+18^2+25^2=949<BR>\n" );
document.write( "hypot=30.81 km<BR>\n" );
document.write( "The angle centered on the port has two parts, one the departure S 25 W, and the other the return bearing.<BR>\n" );
document.write( "The tangent of that angle equals 25/18, so the angle is 54.25 deg<BR>\n" );
document.write( "The bearing away from the port is S 29.25 deg E (the difference).  The bearing is the reciprocal.  <BR>\n" );
document.write( "Converting to degrees, the bearing away from the port is 150.75 deg, so the bearing towards the port is 330.75 deg or W 60.75 N. </SPAN>\n" );
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