document.write( "Question 1112741:
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document.write( "On a Friday night, 26% of the students at a university go out for pizza, 10% see a movie, 26% go to a party, and 38% stay home to study. 24 students are randomly selected. Can the probability that exactly 7 out of these students stay home be computed using a binomial model? \n" );
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Algebra.Com's Answer #728019 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Yes, because there are two possible outcomes, one that would be considered a successful outcome of the experiment and the other a failed outcome and the probability of success for any given trial is constant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, in view of the fact that your given data is ambiguous in one sense, there will be two possible answers to the question.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Does \"see a movie\" mean to put on a DVD and STAY HOME to watch it? Or does it mean GO OUT to a theater? In the first case, the chance of success on a given trial is 48%. In the second case, the chance of success on a given trial is 38%. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |