document.write( "Question 1891: A rectangular picture measures 8” by 11” before it is framed. The frame has a uniform width, and the total area of the picture and the frame is 238 square inches. What is the width of the frame? \n" ); document.write( "

Algebra.Com's Answer #728 by longjonsilver(2297) $\"\"$ $\"About$

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Let the width of the frame be x inches\r
\n" ); document.write( "\n" ); document.write( "the picture is 8x11, so its area is 88 square inches.\r
\n" ); document.write( "\n" ); document.write( "the picture and frame combined is (8+2x)*(11+2x), which equals an area of 238 square inches.\r
\n" ); document.write( "\n" ); document.write( "So lets expand this equation and see what it gives...\r
\n" ); document.write( "\n" ); document.write( " $\"88+%2B+16x+%2B+22x+%2B+4x%5E2+=+238\"$
\n" ); document.write( " $\"4x%5E2+%2B+38x+%2B+88+=+238\"$
\n" ); document.write( " $\"4x%5E2+%2B+38x+-+150+=+0\"$
\n" ); document.write( " $\"2x%5E2+%2B+19x+-+75+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%282x%2B25%29%28x-3%29+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "hence 2x+25=0 or x-3=0\r
\n" ); document.write( "\n" ); document.write( "ignore the first, since this is a negative value. Answer is x=3\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon \n" ); document.write( "

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