document.write( "Question 99884: an investment adviser invested $14000 in two accounts. one investment earned 8% annual simple interest, an the other investment earned 6.5% annual simple interest. the amount of interest earned for 1 year was $1024. how much was investedin each account? \n" ); document.write( "
Algebra.Com's Answer #72798 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
.08X+.065(14000-X)=1024
\n" ); document.write( ".08X+910-.065X=1024
\n" ); document.write( ".015X=1024-910
\n" ); document.write( ".015X=114
\n" ); document.write( "X=114/.015
\n" ); document.write( "X=7600 INVESTED @ 8%
\n" ); document.write( "14000-7600=6400 INVESTED @ 6.5%
\n" ); document.write( "PROOF
\n" ); document.write( ".08*7600+.065*6400=1024
\n" ); document.write( "608+416=1024
\n" ); document.write( "1024=1024
\n" ); document.write( "
\n" ); document.write( "
\n" );