document.write( "Question 1112879: Solve 3sec^2 = 2tanx + 4 = 0. For x is less than or equal to 360 \n" ); document.write( "
Algebra.Com's Answer #727956 by mananth(16946)\"\" \"About 
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3sec^2 = 2tanx + 4 = 0.\r
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\n" ); document.write( "\n" ); document.write( "\"3sec%5E2%28x%29+=+2tanx+%2B+4+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%281%2Btan%5E2%28x%29%29=2tanx+%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"3%281%2Btan%5E2%28x%29%29-2tanx+-4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2B3tan%5E2%28x%29-2tanx+-4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3tan%5E2%28x%29-2tanx+-1=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3tan%5E2%28x%29-3tanx%2Btanx+-1=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3tan%28x%29%28tanx-1%29%2B1%28tanx+-1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28tanx-1%29%283tanx%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "tanx = 1 or tanx = -1/3\r
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