document.write( "Question 1112890: Two trains leave towns 692 mi apart at the same time and travel toward each other. One train travels
\n" ); document.write( "21/mi/h slower than the other. If they meet in 4 hours, what is the rate of each train?
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Algebra.Com's Answer #727925 by josmiceli(19441)\"\" \"About 
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Let \"+s+\" = the speed of the faster car in mi/hr
\n" ); document.write( "\"+s+-+21+\" = the speed of the slower car
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\n" ); document.write( "You can think of this as one of the cars travelling
\n" ); document.write( "at the sum of their speeds and the other one
\n" ); document.write( "standing still
\n" ); document.write( "\"+692+=+%28+s+%2B+s+-+21+%29%2A4+\"
\n" ); document.write( "\"+4%2A%28+2s+-+21+%29+=+692+\"
\n" ); document.write( "\"+8s+-+84+=+692+\"
\n" ); document.write( "\"+8s+=+776+\"
\n" ); document.write( "\"+s+=+97+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+-+21+=+76+\"
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\n" ); document.write( "The faster train's rate is 97 mi/hr
\n" ); document.write( "The slower train's rate is 76 mi/hr
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\n" ); document.write( "check:
\n" ); document.write( "\"+d%5B1%5D+=+97%2A4+\"
\n" ); document.write( "\"+d%5B1%5D+=+388+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+76%2A4+\"
\n" ); document.write( "\"+d%5B2%5D+=+304+\"
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+388+%2B+304+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+692+\"
\n" ); document.write( "OK
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