document.write( "Question 1112880: Solve 3sin^2x + 2cosx + 1 = 0. For x is less than or equal to 360 \n" ); document.write( "
Algebra.Com's Answer #727908 by Alan3354(69443)\"\" \"About 
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Solve 3sin^2x + 2cosx + 1 = 0. For x <= 360
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\n" ); document.write( "Sub 1 - cos^2(x) for sin^2(x)
\n" ); document.write( "--> a quadratic in cos(x)
\n" ); document.write( "Solve for cosine, sub u for cos(x) if that is helpful.
\n" ); document.write( "Solve for x.
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