document.write( "Question 1112838: Simplify the lefthandside so that LHS=RHS\r
\n" ); document.write( "\n" ); document.write( "2/sin(b) = sin(b)/cos(b)-1 + sin(b)/cos(b)+1\r
\n" ); document.write( "\n" ); document.write( "This is a trig identity and I have no clue how to reach my goal on the left-hand side.
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Algebra.Com's Answer #727869 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "No; it is NOT a trig identity -- so you can't prove it.

\n" ); document.write( "The RHS as you show it is
\n" ); document.write( "\"sin%28b%29%2Fcos%28b%29-1+%2B+sin%28b%29%2Fcos%28b%29%2B1\"
\n" ); document.write( "which clearly simplifies to \"2%2A%28sin%28b%29%2Fcos%28b%29%29\" or \"2tan%28b%29\"

\n" ); document.write( "That is not equivalent to \"2%2Fsin%28b%29\"

\n" ); document.write( "What you undoubtedly meant to write on the RHS was
\n" ); document.write( "\"sin%28b%29%2F%28cos%28b%29-1%29+%2B+sin%28b%29%2F%28cos%28b%29%2B1%29\"
\n" ); document.write( "That expression can be simplified nicely; but it too is NOT equivalent to \"2%2Fsin%28b%29\".

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