document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1112828>Question 1112828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a circle the circumference and diameter vary directly. Without using a value of pi, find the diameter of a circle with a circumference of 154 if you know that in a second circle the diameter is 14 when the circumference is 44.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #727835 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=727835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a circle the circumference and diameter vary directly. <BR>\n" );
document.write( "Without using a value of pi, find the diameter of a circle with a circumference of 154 if you know that in a second circle the diameter is 14 when the circumference is 44. <BR>\n" );
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document.write( "44/14 = 154/d<BR>\n" );
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