document.write( "Question 1112670: a parabolic trough 10 meters long 4 meters wide cross the top and 3 meters deep is filled with water at depth of 2 meters. Find the volume of the water in the through \n" ); document.write( "
Algebra.Com's Answer #727820 by Alan3354(69443)\"\" \"About 
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a parabolic trough 10 meters long 4 meters wide cross the top and 3 meters deep is filled with water at depth of 2 meters. Find the volume of the water in the through
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\n" ); document.write( "Find the equation of the parabola.
\n" ); document.write( "Make the x-axis the top of the trough.
\n" ); document.write( "--> y = ax^2 - 3 and the 2 points (-2,0) and (2,0)
\n" ); document.write( "0 = a*4 - 3
\n" ); document.write( "a = 3/4
\n" ); document.write( "--> y = 3x^2/4 -3 is the parabola.\r
\n" ); document.write( "\n" ); document.write( "Find the intersections of the parabola and the line y = -1.
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\n" ); document.write( "-1 = 3x^2/4 - 3
\n" ); document.write( "x^2 = 8/3
\n" ); document.write( "x = +/- sqrt(24)/3
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\n" ); document.write( "Translating the parabola up 1 unit --> the zeroes are x = +/- sqrt(24)/3 and a 3rd point is (0,-2)
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\n" ); document.write( "y = ax^2 - 2
\n" ); document.write( "0 = a*24/9 - 2
\n" ); document.write( "a = 2*(9/24)
\n" ); document.write( "a = 3/4
\n" ); document.write( "--> y = 3x^2/4 - 2
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\n" ); document.write( "INT(3x^2/4 -2) = x^3/4 - 2x + C
\n" ); document.write( "Find area from x = 0 to x = sqrt(24)/3
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\n" ); document.write( "Area of one side = (sqrt(24)/3)^3 - 2sqrt(24)/3 sq meters
\n" ); document.write( "= (24/9)*sqrt(24)/3 - 2sqrt(24)/3
\n" ); document.write( "= 8sqrt(24)/9 - 2sqrt(24)/3
\n" ); document.write( "= 4sqrt(6)/9
\n" ); document.write( "2 times --> 8sqrt(6)/9 sq meters area of the parabola
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\n" ); document.write( "Vol = area*length = 80sqrt(6)/9 cubic meters\r
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