document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99970>Question 99970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help.  I have one last problem on my test due tonight.  I know I am not giving you a lot of time but the person that usually helps me has ended up in the hospital and I am stuck on this last question.\r<BR>\n" );
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document.write( "Solve sqrt2x-1=sqrt4x-1 with another -1 outside the sqrt part.\r<BR>\n" );
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document.write( "Thanks if you have the time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72782 by </B><A HREF=/tutors/aboutme.mpl?userid=fastblue><B>fastblue(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fastblue><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Square both sides,gives you 2x-1=((4x-1)SQRT-1)*((4x-1)SQRT-1)<BR>\n" );
document.write( "  gives you 2x-1= (4x-1)+1-2(4x-1)SQRT, move everything to one side<BR>\n" );
document.write( "of the problem and square the following again. SQRT means the previous to the square root.<BR>\n" );
document.write( "(2x-1)-(4x-1) -1 = -2(4x-1)SQRT<BR>\n" );
document.write( "Divide each side by -2 before squareing again.<BR>\n" );
document.write( "This gives you XSQ + 1/4 + X = 4X-1  after squaring(sq means square)<BR>\n" );
document.write( "move everything to one side.<BR>\n" );
document.write( "Xsq -3x +5/4 = 0 <BR>\n" );
document.write( "Multiply by 4, this gives you 4Xsq - 12X + 5=0<BR>\n" );
document.write( "this breaks down to (2x - 1)(2x - 5)=0<BR>\n" );
document.write( "so x=-1/2 and x=2/5 </SPAN>\n" );
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