document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99880>Question 99880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 times the width. if the area of the rectangle is 675 meters squared, find the perimeter of the rectangle in meters </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72775 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W<BR>\n" );
document.write( "678=3W*W<BR>\n" );
document.write( "3W^2=678<BR>\n" );
document.write( "W^2=678/3<BR>\n" );
document.write( "W^2=226<BR>\n" );
document.write( "W=SQRT226<BR>\n" );
document.write( "W=15.033 ANSWER FOR THE WIDTH.<BR>\n" );
document.write( "L=3*15.033=45.1 ANSWER FOR THE LENGTH<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "15.033*45.1=678<BR>\n" );
document.write( "678=678<BR>\n" );
document.write( "PERIMETER=2L+2W<BR>\n" );
document.write( "2*15.033+2*45.1=30.066+90.2=120.266 METERS IS THE ANSWER FOR THE PERIMETER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );