document.write( "Question 1112683: Help Please ! \r
\n" ); document.write( "\n" ); document.write( "A sample of 30 observations is selected from a normal population. The sample mean is 10, and the population standard deviation is 2. Conduct the following test of hypothesis using the 0.10 significance level.\r
\n" ); document.write( "\n" ); document.write( " H0: μ ≤ 9
\n" ); document.write( " H1: μ > 9\r
\n" ); document.write( "\n" ); document.write( "Q1)Is this a one- or two-tailed test?
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\n" ); document.write( "\n" ); document.write( " One-tailed test ?
\n" ); document.write( " Two-tailed test ?\r
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\n" ); document.write( "\n" ); document.write( "Q2)What is the decision rule?
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\n" ); document.write( "\n" ); document.write( " Reject H0 when z > 1.282 ?
\n" ); document.write( " Reject H0 when z ≤ 1.282 ?\r
\n" ); document.write( "\n" ); document.write( "Q3)What is the value of the test statistic? (Round your answer to 2 decimal places.)\r
\n" ); document.write( "\n" ); document.write( "Q4) What is your decision regarding H0?
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\n" ); document.write( "\n" ); document.write( " Reject H0
\n" ); document.write( " Fail to reject H0\r
\n" ); document.write( "\n" ); document.write( "Q5) What is the p-value? (Round your answer to 4 decimal places.)\r
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\n" ); document.write( "\n" ); document.write( "Q6) Interpret the p-value? (Round your final answer to 2 decimal places.)
\n" ); document.write( " There is a .......%chance of finding a z value this large by ''Sampling Eror'' When H0 is true\r
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Algebra.Com's Answer #727735 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Two tail tests have an equal not equal dichotomy. This is one tail.
\n" ); document.write( "The null hypothesis has mean of 9 and the sample has mean 10. The z test will be positive z >1.282
\n" ); document.write( "value of test statistic
\n" ); document.write( "z=(x-mean)/sigma/sqrt(n)
\n" ); document.write( "=(10-9)/2/sqrt(30)=1*sqrt(30)/2=2.74
\n" ); document.write( "Reject Ho
\n" ); document.write( "p-value is probability z > 2.74, and that is 0.0031.\r
\n" ); document.write( "\n" ); document.write( "If this result were by chance, it would occur about 3 times in a 1000. or 0.31% of the time.
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