document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99945>Question 99945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I just don't understand this.\r<BR>\n" );
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document.write( "In the following system of linear equations, state how to combine the two equations to obtain one equation with only one variable. \r<BR>\n" );
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document.write( "2x - 7y = 6 \r<BR>\n" );
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document.write( "x + 3y = 2 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72770 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+3Y=2 OR X=2-3Y NOW REPLACE X IN THE OTHER EQUATION WITH(2-3Y) & SOLVE FOR Y.<BR>\n" );
document.write( "2(2-3Y)-7Y=6<BR>\n" );
document.write( "4-6Y-7Y=6<BR>\n" );
document.write( "-13Y=6-2<BR>\n" );
document.write( "-13Y=4<BR>\n" );
document.write( "Y=4/-13<BR>\n" );
document.write( "Y=-4/13 ANSWER.<BR>\n" );
document.write( "X+3*-4/13=2<BR>\n" );
document.write( "X-12/13=2<BR>\n" );
document.write( "X=12/13+2<BR>\n" );
document.write( "X=2 12/13 OR 38/13 ANSWER. </SPAN>\n" );
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