document.write( "Question 14590: Solve equation: 2-3(q-1) = 10-(q+1)
\n" ); document.write( "Not sure on how to solve this one. Please help. \n" ); document.write( "

Algebra.Com's Answer #7277 by rahman(247) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2-3%28q-1%29+=+10-%28q%2B1%29\"$
\n" ); document.write( " $\"2-3%2Aq%2B3%2A1+=+10-q-1\"$
\n" ); document.write( " $\"2-3q%2B3+=+10-q-1\"$
\n" ); document.write( " $\"2%2B3-3q+=+10-1-q\"$
\n" ); document.write( " $\"5-3q+=+9-q\"$
\n" ); document.write( " $\"-3q%2Bq+=+9-5\"$
\n" ); document.write( " $\"-2q+=+4\"$
\n" ); document.write( " $\"%28-2q%29%2F%28-2%29+=+4%2F-2\"$
\n" ); document.write( "q=-2\r
\n" ); document.write( "\n" ); document.write( "OK \n" ); document.write( "

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