document.write( "Question 1112570: Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- and y-variables. Solve the system by the elimination method. Be sure to state your final answer in terms of the original question.\r
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document.write( "A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing either $3,000 or $6,000. If the partnership raised $246,000, then how many investors contributed $3,000 and how many contributed $6,000?\r
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document.write( "x = $3,000 investors\r
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document.write( "y = $6,000 investors
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Algebra.Com's Answer #727699 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "$6,000 x Investors 60 \n" ); document.write( "$3,000 y Investors $246,000 \n" ); document.write( "Equation for total investors \n" ); document.write( " \n" ); document.write( " x + y = 60 .............1 \n" ); document.write( " \n" ); document.write( "Equation for amount raised \n" ); document.write( "$6,000 x + 3000.00 y = $246,000 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -3000 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-3000 x -3000 y = -180000 \n" ); document.write( "6000 3000 y = 246000 \n" ); document.write( "Add the two equations \n" ); document.write( "3000 x = 66000 \n" ); document.write( "/ 3000.00 \n" ); document.write( "x = 22.00 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1.00 x + 1.00 y = 60 \n" ); document.write( "22.00 + 1.00 y = 60 \n" ); document.write( " 1.00 y = 38 \n" ); document.write( " y= 38 \n" ); document.write( " \n" ); document.write( "$6000.00 22.00 Investors \n" ); document.write( "$3000.00 38.00 Investors \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |