document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99961>Question 99961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sqaure has side s. the radius of a circle is two less than half the side of the square.<BR>\n" );
document.write( "a. write an expression for the radius of the circle in terms of s.<BR>\n" );
document.write( "b. find the circumference and the area of the circle in terms of pie if s = 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72763 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) (s/2)-2=r<BR>\n" );
document.write( "b) r=12/2-2=4<BR>\n" );
document.write( "C=2*pi*r=8*pi<BR>\n" );
document.write( "A=pi*r^2=pi*16<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );