document.write( "Question 1112541: Felipe drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 10 hours. When Felipe drove home, there was no traffiand the trip only took 7hours. If his average rate was 18miles per hour faster on the trip home, how far away does Felipe live from the mountains? \n" ); document.write( "

Algebra.Com's Answer #727594 by mananth(16946) $\"\"$ $\"About$

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\n" ); document.write( "To mountains x mph
\n" ); document.write( "From mountains 18 mph faster
\n" ); document.write( "returning speed x + 18
\n" ); document.write( "returning time = 7 hours
\n" ); document.write( "going out time= 10 hours
\n" ); document.write( "
\n" ); document.write( "Distance = same \r
\n" ); document.write( "\n" ); document.write( "10 x = 7 ( x + 18 )
\n" ); document.write( "10 x = 7 x + 126
\n" ); document.write( "10 x - -7 x = 126
\n" ); document.write( "3 x = -50 126
\n" ); document.write( "/ 3
\n" ); document.write( "x = 42 mph
\n" ); document.write( "
\n" ); document.write( "Returning speed=60 mph\r
\n" ); document.write( "\n" ); document.write( "Distance = 42*10 =420 miles
\n" ); document.write( "OR
\n" ); document.write( "Distance = (42+18) * 7= 420 miles\r
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