document.write( "Question 1112494: The present age of a women is 4 times as her daughter's age. When the women was 29 years old, her only son, who is two years younger than her only daughter, was born. What is the present age of the son? \n" ); document.write( "
Algebra.Com's Answer #727572 by MathTherapy(10552)\"\" \"About 
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The present age of a women is 4 times as her daughter's age. When the women was 29 years old, her only son, who is two years younger than her only daughter, was born. What is the present age of the son?
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Let son’s age be be S
\n" ); document.write( "Then daughter’s is: S + 2
\n" ); document.write( "Woman’s age: S + 29, and also, 4(S + 2)
\n" ); document.write( "We then get: S + 29 = 4(S + 2)
\n" ); document.write( "S + 29 = 4S + 8
\n" ); document.write( "S – 4S = 8 – 29
\n" ); document.write( "– 3S = - 21
\n" ); document.write( "S, or son’s age is: \"highlight_green%28matrix%281%2C3%2C+%28-+21%29%2F%28-+3%29%2C+%22=%22%2C+7%29%29\" \n" ); document.write( "
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